3.30 \(\int \frac {1}{\csc ^{\frac {4}{3}}(a+b x)} \, dx\)

Optimal. Leaf size=53 \[ \frac {3 \cos (a+b x) \, _2F_1\left (\frac {1}{2},\frac {7}{6};\frac {13}{6};\sin ^2(a+b x)\right )}{7 b \sqrt {\cos ^2(a+b x)} \csc ^{\frac {7}{3}}(a+b x)} \]

[Out]

3/7*cos(b*x+a)*hypergeom([1/2, 7/6],[13/6],sin(b*x+a)^2)/b/csc(b*x+a)^(7/3)/(cos(b*x+a)^2)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {3772, 2643} \[ \frac {3 \cos (a+b x) \, _2F_1\left (\frac {1}{2},\frac {7}{6};\frac {13}{6};\sin ^2(a+b x)\right )}{7 b \sqrt {\cos ^2(a+b x)} \csc ^{\frac {7}{3}}(a+b x)} \]

Antiderivative was successfully verified.

[In]

Int[Csc[a + b*x]^(-4/3),x]

[Out]

(3*Cos[a + b*x]*Hypergeometric2F1[1/2, 7/6, 13/6, Sin[a + b*x]^2])/(7*b*Sqrt[Cos[a + b*x]^2]*Csc[a + b*x]^(7/3
))

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rule 3772

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x])^(n - 1)*((Sin[c + d*x]/b)^(n - 1)
*Int[1/(Sin[c + d*x]/b)^n, x]), x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rubi steps

\begin {align*} \int \frac {1}{\csc ^{\frac {4}{3}}(a+b x)} \, dx &=\csc ^{\frac {2}{3}}(a+b x) \sin ^{\frac {2}{3}}(a+b x) \int \sin ^{\frac {4}{3}}(a+b x) \, dx\\ &=\frac {3 \cos (a+b x) \, _2F_1\left (\frac {1}{2},\frac {7}{6};\frac {13}{6};\sin ^2(a+b x)\right )}{7 b \sqrt {\cos ^2(a+b x)} \csc ^{\frac {7}{3}}(a+b x)}\\ \end {align*}

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Mathematica [A]  time = 0.11, size = 68, normalized size = 1.28 \[ -\frac {\cos (a+b x) \left (\, _2F_1\left (\frac {1}{2},\frac {5}{6};\frac {3}{2};\cos ^2(a+b x)\right )+3 \sqrt [6]{\sin ^2(a+b x)}\right )}{4 b \sqrt [6]{\sin ^2(a+b x)} \sqrt [3]{\csc (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[a + b*x]^(-4/3),x]

[Out]

-1/4*(Cos[a + b*x]*(Hypergeometric2F1[1/2, 5/6, 3/2, Cos[a + b*x]^2] + 3*(Sin[a + b*x]^2)^(1/6)))/(b*Csc[a + b
*x]^(1/3)*(Sin[a + b*x]^2)^(1/6))

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fricas [F]  time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{\csc \left (b x + a\right )^{\frac {4}{3}}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="fricas")

[Out]

integral(csc(b*x + a)^(-4/3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\csc \left (b x + a\right )^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="giac")

[Out]

integrate(csc(b*x + a)^(-4/3), x)

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maple [F]  time = 0.61, size = 0, normalized size = 0.00 \[ \int \frac {1}{\csc \left (b x +a \right )^{\frac {4}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/csc(b*x+a)^(4/3),x)

[Out]

int(1/csc(b*x+a)^(4/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\csc \left (b x + a\right )^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="maxima")

[Out]

integrate(csc(b*x + a)^(-4/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{{\left (\frac {1}{\sin \left (a+b\,x\right )}\right )}^{4/3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1/sin(a + b*x))^(4/3),x)

[Out]

int(1/(1/sin(a + b*x))^(4/3), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\csc ^{\frac {4}{3}}{\left (a + b x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)**(4/3),x)

[Out]

Integral(csc(a + b*x)**(-4/3), x)

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